4.905x^2+5x=50

Solution for 4.905x^2+5x=50 equation:

4.905x^2+5x=50

We move all terms to the left:

4.905x^2+5x-(50)=0

a = 4.905; b = 5; c = -50;
Δ = b2-4ac
Δ = 52-4·4.905·(-50)
Δ = 1006
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{1006}}{2*4.905}=\frac{-5-\sqrt{1006}}{9.81}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{1006}}{2*4.905}=\frac{-5+\sqrt{1006}}{9.81}
$